Speed and time question
- August 22, 2012
- Posted by: Kamal Rawat
- Category: Quantitative Aptitude
Two towns are exactly 100 km apart. Suresh leaves City-A at 3 pm driving at 30 km/hr. After 30 minutes, at 3:30 pm, Ramesh leaves City-B driving at 60 km/hr.
When they meat each other, how far they will be from City-A ?
Suresh starts 30 minutes before Ramesh.
In 30 min he would have traveled = 15 km.
When both of them are moving toward each other their relative speed is = 90 km/hr (30+60)
The distance between them is = 85 km (15 km is already traveled by Suresh).
Time taken to cover 85 km @ 90 km/hr = 85/90 hrs = 56.67 min
Distance traveled by Suresh in 56.67 min = 28.34 km.
Total distance from A = distance traveled by Suresh = 15 + 28.34 = 43.34 km.