Computing average of running stream of numbers

Given a stream of numbers (keep reading numbers from the keyboard). Write code to print the average at each point. For example: user is entering the numbers, at each point you should print the average of all the numbers entered till now, as shown below

numbers             Average
------------        -------------
10                    10
10, 20                15
10, 20, 30            20
10, 20, 30, 40        25
10, 20, 30, 40, 50    30
...                   ...
...                   ...

Solution:

One brute force approach is to compute average at each time, when a number is entered. Each average calculation will be O(n). Hence,65 the total time taken will be O(n²).

Better Approach:

When a new number is entered, we consider the previous average and compute the new average in constant time, i.e O(1).

Hence, at every point when a number is entered, we consider the previous average and calculate the new average in O(1) time.

// Prints average of a stream of numbers
 void streamAvg(double arr[], int n)
 {
    float avg = 0;
    for(int i = 0; i < n; i++)
    {
       avg = (avg * i + arr[i])/(i+1);
       printf("Average of %d numbers is %f \n", i+1, avg);
    }
 }