Difference between return & exit(0)

What is the difference between exit(0) and return statement in the main function of a C++ program?

Solution:

When exit(0) is used to exit from a C++ program, the destructor for local non-static objects is not called.

    class MyClass
    {
        public:
        // Constructor
        MyClass() { cout<< "Constructor" << endl; }
        // Destructor
        MyClass() { cout<< "Destructor" << endl; }
    };
    int main()
    {
        MyClass obj;
        // Using exit
        exit(0);
    }

Output:

Constructor

If we do a return from the main, then the implementation will make sure that the destructor is called

    class MyClass
    {
        public:
        // Constructor
        MyClass() { cout<< "Constructor" << endl; }
        // Destructor
        MyClass() { cout<< "Destructor" << endl; }
    };
    int main()
    {
        MyClass obj;
        // Using return
        return 0;
    }

Output:

Constructor Destructor

For static and global variables, the destructor may get called (depending on the compiler implementation).

    class MyClass
    {
        public:
        // Constructor
        MyClass() { cout<< "Constructor" << endl; }
        // Destructor
        MyClass() { cout<< "Destructor" << endl; }
    };
    int main()
    {
        static MyClass obj;
        // Using exit
        exit(0);
    }

Output:

Implementation Dependent 

This is because static & global variables are load-time variables and are allocated memory in the data area (which is independent of function calls) and not in the Activation Record of a function.

Load time variables are cleaned up by the start-up library.